Resultados da pesquisa

coordenadas ( h , k , l ) {\displaystyle (h,k,l)\,\!} , a distância entre os pontos é: D 3 a b = ( x − h ) 2 + ( y − k ) 2 + ( z − l ) 2 {\displaystyle D3_{ab}={\sqrt...

ignorados durante a compactação. -k [arquivo] Modifica o [arquivo] para ter compatibilidade total com o pkzip do DOS. -l Converte saltos de linha UNIX (LF)...

Aqui encontraremos diversas ferramentas Web 2.0 e verbetes/tópicos úteis que ajudarão os Agentes TEIA MG em seus projetos. As ferramentas estão organizadas...

D, E, F, G, Ĝ, H, Ĥ, I, J, Ĵ, K, L, M, N, O, P, R, S, Ŝ, T, U, Ŭ, V, Z a, b, c, ĉ, d, e, f, g, ĝ, h, ĥ, i, j, ĵ, k, l, m, n, o, p, r, s, ŝ, t, u, ŭ,...

estabilizando-se. K: 19 elétrons (K=2, L=8, M=8, N=1) P: 15 elétrons (K=2, L=8, M=5) K + K + K + P → K 3 + P − − − {\displaystyle K+K+K+P\to K_{3}^{+}P^{---}}...

1 ( r 1 + r 2 ) 2 {\displaystyle \mu \;=\;{\frac {2\Omega (r_{2}\;-\;r_{1})}{\pi r_{1}l\omega _{1}(r_{1}\;+\;r_{2})^{2}}}} = 2 ⋅ 9.0 k g ⋅ c m ⋅ ( 12.6...

t}+2={\color {blue}k_{1}e^{t}+k_{2}e^{-t}+2}} Concavidade ∂2L∂x(t)2=−2{\displaystyle {\partial ^{2}L \over \partial x(t)^{2}}=-2} ∂2L∂x(t)∂x′(t)=0{\displaystyle...

alternativa P 2 = ρ 2 g h 2 Φ 2 ⇒ P a 2 = 1000 k g / m 3 ⋅ 9.8 m / s 2 ⋅ 15 m ⋅ 2200 l / m i n 0.8 {\displaystyle P_{2}\;=\;\rho _{2}gh_{2}\Phi _{2}\;\;\;\Rightarrow...

m ρ o v o 2 L o 2 ρ m v m 2 L m 2 = 30 N ⋅ 1000 k g / m 3 ⋅ ( 8 k m / h ) 2 ⋅ ( 50 c m ) 2 1.2 k g / m 3 ⋅ ( 110 m / s ) 2 ⋅ ( 10 c m ) 2 {\displaystyle...

0<|x−a|< δ2{\displaystyle 0<|x-a|<\ \delta _{2}} e |f(x)−L| < k|M|+1{\displaystyle |f(x)-L|\ <\ {\frac {k}{|M|+1}}}(3), se x∈Df{\displaystyle x\in D_{f}}...

então: x k → x ¯ {\displaystyle x_{k}\to {\bar {x}}} l ρ ( x k , u k ) → f ( x ¯ ) {\displaystyle l_{\rho }(x_{k},u_{k})\to f({\bar {x}})} { u k } {\displaystyle...

mudar 10 litros de Hélio a 100 K e 0,1 atm para 20 l a 0,2 atm. T f = T i P f V f P i V i = 100 ⋅ 0 , 2 ⋅ 20 10 ⋅ 0 , 1 = 400 K = 127 o C {\displaystyle...

name, right? B: Right. And my last name is Pohlansky. P – O – H – L – A – N – S – K – Y. A: Thank you. C: What’s her name? A: It’s Svenja Pohlansky. C:...

\;D}{\pi D^{2}\;\mu _{0}}}\;=\;{\frac {4\rho _{0}\;\Phi }{\pi D\;\mu _{0}}}} N R e = 4 ⋅ 1000 k g / m 3 ⋅ 10 l / s 3.14 ⋅ 60 m m ⋅ 0.0010 k g ⋅ m − 1 ⋅...

que g Δ h = 1 2 ( N f i + N f l L D + 1 ) v ¯ 2 ⇒ N f l D = 1 L ( 2 g Δ h v ¯ 2 − N f i − 1 ) {\displaystyle g\;\Delta h\;=\;{\frac {1}{2...

sabemos que g Δ h = 1 2 ( N f i + N f l L D + 1 ) v ¯ 2 ⇒ v ¯ 2 = 2 g Δ h N f i + N f l L D + 1 {\displaystyle g\;\Delta h\;=\;{\frac {1}{2}}\;\left(N_{fi}\;+\;N_{fl}\;{\frac...

comprimento l 1 {\displaystyle l_{1}\!\,} , outro cateto, o comprimento l 2 {\displaystyle l_{2}\!\,} e a hipotenusa, l 3 {\displaystyle l_{3}\!\,} ; tal...

_{2}\;=\;k_{b}l^{-1}tv} l = k 1 l π 1 + k 2 l π 2 = k 1 g t 2 + k 2 t v {\displaystyle l\;=\;k_{1}\;l\;\pi _{1}\;+\;k_{2}\;l\;\pi _{2}\;=\;k_{1}gt^{2}\;+\;k_{2}tv}...

equação, teremos ∂ ∂ r ( r ∂ v z ∂ r ) = 1 μ 0 Δ p L r ⇒ r ∂ v z ∂ r = k 1 r 2 + k 2 ( k 1 = 1 2 μ 0 Δ p L ) {\displaystyle {\frac {\partial }{\partial r}}\left(r\;{\frac...

l ( c − t l − 1 )  como  m l ≤ m ′  e  m l ≤ m ″ {\displaystyle m_{l}(t_{l}-t_{l-1})=m_{l}(t_{l}-c+c-t_{l-1})=m_{l}(t_{l}-c)+m_{l}(c-t_{l-1}){\mbox{...